Machine A has 60° phase spread and machine B has 120° phase spread. Both the machines have uniformly distributed winding. The ratio of distribution factors of machine A to machine B is ____________

Correct Answer: 1.55
kdA=(sinσ/2)/σ/2, σ=60° ⇒ kdA=0.9556 kdB=(sinσ/2)/σ/2, σ=120° ⇒ kdB=0.827 thus, kdA/kdB=1.155.