What is the torque provided by a rotating object which is being rotated with a force of 6N and radial distance of point of application of the force from the centre is 2m? (Consider the radial distance vector and force vector are at 30° to each other)

Correct Answer: 6 Nm
GiveForce(f)=6N Radial distance(r)=2m Angle between radial distance vector and force vector (θ)=30° We know; Torque (t)=f*r*sinθ Torque (t)=6*2*sin(30°) Torque (t)=6Nm