Arrange the series of step involved in designing a filter for first order low pass filter Step 1: Select a value of C less than or equal to 1µF Step 2: Choose a value of high cut-off frequency fH Step 3: Select a value of R1C and RF depending on the desired pass band gain Step 4: Calculate the value of R

Steps- 2->4->3->1

Steps- 4->1->3->2

Steps- 2->1->4->3

Steps- 1->3->4->2

The mentioned option is the sequence of steps followed for designing a low pass filter.

Find the gain and phase angle of the second order low pass filter? Where pass band gain of the filter is 5, frequency and the high cut-off frequency of the filter are 3000Hz and 1kHz.

None of the mentioned

Gain magnitude = -1.03dB , φ =63.32o

Gain magnitude = -5.19dB , φ =71.56o

Gain magnitude = -4.94dB , φ =90o

From the given specifications, determine the value of voltage gain magnitude of first order and second order high pass butterworth filter? Pass band voltage gain=2; Low cut-off frequency= 1kHz; Input frequency=500Hz.

First order high pass filter =-4.22dB , Second order high pass filter=-0.011dB

First order high pass filter =-0.9688dB , Second order high pass filter=-6.28dB

First order high pass filter =-11.3194dB , Second order high pass filter=-9.3257dB

First order high pass filter =-7.511dB , Second order high pass filter=-5.8999dB

If H(s) is the transfer function of a analog low pass normalized filter and Ωu is the desired pass band edge frequency of new low pass filter, then which of the following transformation has to be performed?

s → s / Ωu

s → s.Ωu

s → Ωu/s

None of the mentioned

The low pass, high pass, band pass and band stop filters can be designed by applying a specific transformation to a normalized low pass filter.

True

False

The low-pass active filter shown in the figure has a cut-off frequency of 2 kHz and a pass band gain of 1.5. The values of the resistors are

R1 = 10 k$$\Omega $$; R2 = 1.3 $$\Omega $$

R1 = 30 k$$\Omega $$; R2 = 1.3 $$\Omega $$

R1 = 10 k$$\Omega $$; R2 = 1.7 $$\Omega $$

R1 = 30 k$$\Omega $$; R2 = 1.7 $$\Omega $$

Consider an open loop circuit with lower cutoff frequency 5kHz and upper cutoff frequency 20kHz. If negative feedback is applied to the same, choose correct option stating the new cutoff frequencies.

Lower cutoff = 5kHz, Upper cutoff = 20kHz

Lower cutoff = 2kHz, Upper cutoff = 18kHz

Lower cutoff = 2kHz, Upper cutoff = 25kHz

Lower cutoff = 10kHz, Upper cutoff = 25kHz

Compute the pass band gain and high cut-off frequency for the first order high pass filter.

AF=11, fH=796.18Hz

AF=10, fH=796.18Hz

AF=2, fH=796.18Hz

AF=3, fH=796.18Hz

If F1 and F2 are the lower and upper cutoff frequencies of a band pass signal, then what is the condition to be satisfied to call such a band pass signal as narrow band signal?

(F1-F2)>$\frac{F_1+F_2}{2}$(factor of 3 or less)

(F1-F2)⋙$\frac{F_1+F_2}{2}$(factor of 10 or more)

(F1-F2)<$\frac{F_1+F_2}{2}$(factor of 3 or less)

(F1-F2)⋘$\frac{F_1+F_2}{2}$(factor of 10 or more)

A second order low pass filter is given an input frequency of 30kHz and produce a output having phase angle of 79o. Determine the pass band gain of the filter?

11 dB

89.11 dB

46.78 dB

None of the mentioned

If the low pass filter described by the difference equation y(n)=0.9y(n-1)+0.1x(n) is converted into a high pass filter, then what is the frequency response of the high pass filter?

0.1/(1+0.9ejω)

0.1/(1+0.9e-jω)

0.1/(1-0.9ejω)

None of the mentioned