Bissoy
Login
Get Advice on Live Video Call
Earn $ Cash $ with
consultations on Bissoy App
Determine RMS pulse broadening with mode coupling if pulse broadening is 0.6 over 8km.
A
1.6ns
B
1.7ns
C
1.5ns
D
1.4ns
Correct Answer:
1.7ns
Total RMS pulse broadening with mode coupling is given by- σT = σ√L. Here σT = RMS pulse broadening, L = length of the fiber.
Determine total RMS pulse broadening over 8 km if RMS pulse broadening is 0.6ns/km.
A
3.6 ns
B
4 ns
C
4.8 ns
D
3 ns
Determine RMS pulse broadening over 8 km if total RMS pulse broadening is 5.8ns/km.
A
0.2ns/km
B
0.1ns/km
C
0.4ns/km
D
0.72ns/km
A multimode fiber has RMS pulse broadening per km of 12ns/km and 28ns/km due to material dispersion and intermodal dispersion resp. Find the total RMS pulse broadening.
A
30.46ns/km
B
31.23ns/km
C
28.12ns/km
D
26.10ns/km
A machine started malfunctioning due to some issues with the coupling. The coupling emplaced in the machine was Oldham. The only coupling available in the workshop is Hooke’s coupling. So Oldham coupling can be replaced by Hooke’s coupling.
A
True
B
False
Determine dispersion equalization penalty without mode coupling if BT is 150 Mbits/s and total rms pulse broadening is 4.8ns.
A
34 dB
B
33 dB
C
76.12 dB
D
34.38 dB
Estimate RMS pulse broadening per km due to intermodal dispersion for multimode step index fiber where length of fiber is 4 km and pulse broadening per km is 80.6 ns.
A
18.23ns/km
B
20.15ns/km
C
26.93ns/km
D
10.23ns/km
A multimode step index fiber has source of RMS spectral width of 60nm and dispersion parameter for fiber is 150psnm-1km-1. Estimate rms pulse broadening due to material dispersion.
A
12.5ns km-1
B
9.6ns km-1
C
9.0ns km-1
D
10.2ns km-1
A multimode step index fiber has source of RMS spectral width of 60nm and dispersion parameter for fiber is 150psnm
-1
km
-1
. Estimate rms pulse broadening due to material dispersion.
A
12.5ns km<sup>-1</sup>
B
9.6ns km<sup>-1</sup>
C
9.0ns km<sup>-1</sup>
D
10.2ns km<sup>-1</sup>
Rahul travels 8km towards east, turns right andtravels another 6km, and then takes two successive leftturns covering 21km and 6km in each turn respectively.Finally, he takes a right turn and travels 8km further. Howfar is he now from his original position?
A
35km
B
25km
C
37km
D
40km
Simplify : $${{{5 \over 3} \times {7 \over {51}}{\text{ of }}{{17} \over 5} - {1 \over 3}} \over {{2 \over 9} \times {5 \over 7}{\text{ of }}{{28} \over 5} - {2 \over 3}}}$$
A
$$\frac{1}{2}$$
B
4
C
2
D
$$\frac{1}{4}$$