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24 channels, each band limited to 3.4 KHz, are to be time division multiplexed. Find the bandwidth required for 128 quantization level? (Given that sampling frequency is 8 KHz)

Correct Answer: 1536 KHz
N = 24, fm = 3.4 kHz m = 128, 2n = m = 128, n = 7 But fs = 2fm, where, fs = sampling frequency instead at 2fm 2 x 3.4 kHz 6.8 KHz. B.W. = N(n+1)X fs = 8 kHz = 1536 KHz.

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