If a sample water has not supplied any heat and having impurities as follows: Mg(HCO3)2=50 mg of CaCO3, MgSO4 = 100mg of CaCO3, CaCl2=200mg of CaCO3, Ca(NO3)2=100mg of CaCO3. Calculate the lime required for treatment of 10000 litres of water.

Correct Answer: 1.48Kg
Lime needed is 0.74. So, 0.74(0+2*50+100)=148mg/litre. Lime requirement for 10000 litres of water is 148*10000mg=1.48Kg.