A sample of coal containing the following elements: C=90%; H=5%; ash=4%; weight of the coal burnt=0.90g; weight of the water taken=600g; water equivalent of bomb calorimeter=2000g; rise in temperature=2.48oC; fuse wire correction=10cal; cooling correction=0.02oC; acid correction=50 cal. Calculate net and GCV of coal in cal/g. Assume latent heat of steam is 580cal/g.

Correct Answer: HCV=7155.55cal/g; NCV=6894.55cal/g
For HCV we can use the formula HCV = (W+w) (t2-t1+cooling corrections)-(acid + fuse corrections)/weight of the fuel. So, the NCV can be given by subtracting the 0.09H*latent heat of steam from HCV.