A float occupies 4 bytes. If the hexadecimal equivalent of these 4 bytes are A, B, C and D, then when this float is stored in memory in which of the following order do these bytes gets stored?
Correct Answer: Depends on big endian or little endian architecture
“Little Endian” means that the lower-order byte of the number is stored in memory at the lowest address, and the high order byte at the highest address. For example, a 4 byte Integer ABCD will be arranged in memory as follows: Base Address + 0 Byte 0. Base Address + 1 Byte 1. Base Address + 2 Byte 2. Base Address + 3 Byte 3. Intel processors (those used in PC’s) use “Little Endian” byte order. “Big Endian” means that the high-order byte of the number is stored in memory at the lowest address, and the low-order byte at the highest address. The same 4 byte integer would be stored as: Base Address + 0 Byte 3. Base Address + 1 Byte 2. Base Address + 2 Byte 1. Base Address + 3 Byte 0.