Given two processes (conversion of postfix equation to infix notation and conversion of prefix notation to infix notation), which of the following is easier to implement?

Both are easy to implement

Conversion of postfix equation to infix equation is harder than converting a prefix notation to infix notation

Conversion of postfix equation to infix equation is easier than converting a prefix notation to infix notation

Insufficient data

Correct Answer: Conversion of postfix equation to infix equation is easier than converting a prefix notation to infix notation

As the conversion of prefix notation to infix notation involves reversing the equation, the latter is harder to implement than postfix to infix process.

Here is an infix expression: 4 + 3(63-12). Suppose that we are using the usual stack algorithm to convert the expression from infix to postfix notation. The maximum number of symbols that will appear on the stack AT ONE TIME during the conversion of this expression?

Which data structure is needed to convert infix notation to postfix notation?

Tree

Branch

Stack

Queue

What data structure is used when converting an infix notation to prefix notation?

Stack

Queue

B-Trees

Linked-list

When converting the prefix notation into an infix notation, the first step to be followed is ________

Reverse the equation

Push the equation to the stack

Push the equation onto the queue

Push the equation to the stack or queue

The time complexity of converting a prefix notation to infix notation is _________

O(n) where n is the length of the equation

O(n) where n is number of operands

O(1)

O(logn) where n is length of the equation

To convert the postfix expression into the infix expression we use stack and scan the postfix expression from left to right.

True

False

It is easier for a computer to process a postfix expression than an infix expression.

True

False

Given a prefix and a postfix notation what are the difference between them?

The postfix equation is solved starting from the left whereas the prefix notation is solved from the right

The postfix equation is solved starting from the right whereas the prefix notation is solved from the left

Both equations are solved starting from the same side(right)

Both equations are solved starting from the same side(left)

Which of the following statement is incorrect with respect to infix to postfix conversion algorithm?

operand is always placed in the output

operator is placed in the stack when the stack operator has lower precedence

parenthesis are included in the output

higher and equal priority operators follow the same condition

What is the time complexity of an infix to postfix conversion algorithm?

O(N log N)

O(N)

O(N2)

O(M log N)