Given that capacitance w.r.t the input node is 2pF and output node is 4pF, find capacitance between input and output node.

Correct Answer: 0.67 pF
C1=C(1-K), C2=C(1-K-1) C1=2pF C2=4pF C1/C2=1/2=1-K/1-K-1 K = -2 C1 = C(1+2) = 3C C = C1/3 = 2/3pF = 0.67 pF.