Eighteen years ago , a father was three times as old as his son. Now the father is only twice as old as his son. Then the sum of the present ages of the son and the father is-

Correct Answer: 108
Let, now son is x years old So, father is 2x years old 18 years ago son was ( x - 18) years old and, 18 years ago father was ( 2x - 18) years old On condition, 2x - 18 = 3 ( x - 18) 2x - 18 = 3x - 54 - x = - 36 x = 36 So, son is 36 years old and Father is 36×2 or 72 years old Sum of sons and fathers age = (36 + 72) years = 108 years