Bissoy
Login
Get Advice on Live Video Call
Earn $ Cash $ with
consultations on Bissoy App
An inverting amplifier with nominal gain of −20 V/V employs an op amp having a dc gain of 104 and a unity-gain frequency of 106 Hz. What is the 3-dB frequency f3dB of the closed-loop amplifier?
A
2π 23.8 kHz
B
2π 47.6 kHz
C
2π 71.4 kHz
D
2π 95.2 kHz
Correct Answer:
2π 47.6 kHz
n:
Consider the 5 × 5 matrix \[{\text{A}} = \left[ {\begin{array}{*{20}{c}} 1&2&3&4&5 \\ 5&1&2&3&4 \\ 4&5&1&2&3 \\ 3&4&5&1&2 \\ 2&3&4&5&1 \end{array}} \right
A
\
B
<br>It is given that A has only one real eigen value.<br>Then the real eigen value of A is
C
<p><span>A.</span> -2.5
D
</span> 0
Let A be an m × n matrix and Ban n × m matrix. It is given that determinant ($$I$$
m
+ AB) = determinant ($$I$$
n
+ BA), where $$I$$
k
is the k × k identity matrix. Using the above property, the determinant of the matrix given below is
\[\left[ {\begin{array}{*{20}{c}} 2&1&1&1 \\ 1&2&1&1 \\ 1&1&2&1 \\ 1&1&1&2 \end{array}} \right
A
\
B
<p><span>A.</span> 2
C
</span> 5
Eigen values of the matrix \[\left[ {\begin{array}{*{20}{c}} 0&1&0&0 \\ 1&0&0&0 \\ 0&0&0&{ - 2i} \\ 0&0&{2i}&0 \end{array}} \right
A
\
B
are
C
<p><span>A.</span> -2, -1, 1, 2
D
</span> -1, 1, 0, 2
An op amp having a 106-dB gain at dc and a single-pole frequency response with ft = 2 MHz is used to design a non-inverting amplifier with nominal dc gain of 100. The 3-dB frequency of the closed-loop gain is
A
10 kHz
B
20 kHz
C
30 kHz
D
40 kHz
cascading two identical amplifier stages, each having a low-pass STC frequency response with a 3dB frequency f1, results in an overall amplifier with a 3dB frequency given by
A
√(√2+1) f1
B
√(√3-1) f1
C
√(√2-1) f1
D
√(√3+1) f1
A 741-Type OP-amp has a gain-bandwith product of 1MHz. A non-inverting amplifier using this opamp & having a voltage gain of 20db will exhibit -3db bandwidth of
A
50 kHz
B
100 kHz
C
$$\frac{{1000}}{{17}}{\text{ kHz}}$$
D
$$\frac{{1000}}{{7.07}}{\text{ kHz}}$$
In designing with op amps one has to check the limitations on the voltage and frequency ranges of operation of the closed-loop amplifier, imposed by the op-amp finite bandwidth (ft), slew rate (SR), and output saturation (Vo max). Consider the use of an op amp with ftt = 2 MHz, SR = 1 V/µs, and V0 max = 10 V in the design of a non-inverting amplifier with a nominal gain of 10. Assume a sine-wave input with peak amplitude Vi. If Vi = 0.5 V, what is the maximum frequency before the output distorts?
A
31.8 kHz
B
318 kHz
C
3.18 kHz
D
3.18 MHz
In designing with op amps one has to check the limitations on the voltage and frequency ranges of operation of the closed-loop amplifier, imposed by the op-amp finite bandwidth (ft), slew rate (SR), and output saturation (Vo max). Consider the use of an op amp with ftt = 2 MHz, SR = 1 V/µs, and V0 max = 10 V in the design of a non-inverting amplifier with a nominal gain of 10. Assume a sine-wave input with peak amplitude Vi. If f = 20 kHz, what is the maximum value of Vi before the output distorts?
A
0.397 V
B
0.795 V
C
1.192 V
D
1.590 V
A 741-type OP-amp has a gain-bandwidth product of 1MHz. A non-inverting amplifier using this OP-amp & having a voltage gain of 20 db will exhibit -3 db bandwidth of
A
50 KHz
B
100 KHz
C
$$\frac{{1000}}{{17}}{\text{KHz}}$$
D
$$\frac{{1000}}{{7.07}}{\text{KHz}}$$
A certain inverting amplifier has a closed-loop voltage gain of 25. The OP-amp has an open-loop voltage gain of 100,000. If an OP-amp with an open-loop voltage gain of 200,000 is substituted in the arrangement, the closed-loop gain
A
doubles
B
drops to 12.5
C
remains at 25
D
increases slightly