A half wave rectifier, operated from a 50Hz supply uses a 1000µF capacitance connected in parallel to the load of rectifier. What will be the minimum value of load resistance that can be connected across the capacitor if the ripple% not exceeds 5?

Correct Answer: 115.47Ω
For a half wave filter, ϒ=1/2√3 fCRL=1/2√3*50*10-3*RL RL=103/5√3=115.47Ω.