A tapered tube of length 8cm and end diameters 2cm and 4cm connects two vessels containing mixtures of A and B. if the tapered tube is replaced with a cylindrical tube of diameter 6cm, what will be the required length of the cylindrical tube to maintain the same flow rate as in the previous case?

Correct Answer: 36cm
– (Area)*(flux) =Constant=W W1 for cylinder= (πr2 DAB(P1-P2))/RTL W2 for tapered tube = (πDAB*r1*r2(P1-P2))/RTL Equate W1 and W2.