The binding energy of an electron to a proton (i.e., hydrogen atom) is 13.6 eV. The loss of mass in the formation of one atom of hydrogen is _____________

Correct Answer: 2.42 X 10-35 Kg
E = 13.6 eV = 13.6 X 1.6 X 10-19 J Using Einstein’s Mass-energy relation, the loss of mass Δm = E/c2 Δm = 13.6 X 1.6 X 10-19/9 X 1016 = 2.42 X 10-35 Kg.