In a family of 10 members, 7 of them like tea or coffee, 4 of them like tea and 5 of them like coffee. How many of them like both tea and coffee?

Correct Answer: 2
We know, n (T ∪ C) = n (T) + n (C) – n (T ∩ C) Given, n (T ∪ C) = 7, n(T)=4, n(C)=5 7 = 4 + 5 – n (T ∩ C) n (T ∩ C) = 2. Hence, 2 members like both tea and coffee.