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A ring of radius 7cm is rotating about the central axis perpendicular to its plane. A force acts on it, tangentially, such that it does a work of 10J in a complete rotation. Find the value of that force. `

Correct Answer: 500/7π N
Let the force be ‘F’. Work done will be = Tθ, where T is the torque & is the angular displacement = 2π rad. Work = Tθ = 10 ∴ T(2π) = 10 ∴ T = 5/π Nm. Also, T = r*F ∴ 5/π = 0.07*F ∴ F = 500/7π N.

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