Get Advice on Live Video Call
Earn $ Cash $ with
consultations on Bissoy App

Masud has all his office supplies laid out in an orderly way on his desk.The pens are directly to the left of the memos . The lamp cannot be next to the stapler . The memos must be in the middle . The clipboard is to the left of the stapler . Which position is the lamp in ? (giving the positions numbers 1-5 from left to right ).

Correct Answer: 1
Pens are directly to the left of Memos = Pen = memos Lamp cannot be next to the stapler = stapler = lamp Memos must be in the middle = 3rd place Clipboard is to the left of the stapler = Clipboard = stapler so correct answer 1

Lamp A is less bright than Lamp B; Lamp B is less brighter than Lamp C; Lamp C is as bright as Lamp D. Lamp B is brighter than Lamp D and Lamp D is brighter than Lamp A. Which lamp is the brightest ?

Lamp A is less bright than Lamp B; Lamp B is Brighter than lamp C; Lamp C is as bright as Lamp D. Lamp B is brighter than Lamb D and Lamp D is better than Lamp A. Which is the brightest?

If a + b + c + d = 4, then find the value of $$\frac{1}{{\left( {1 - a} \right)\left( {1 - b} \right)\left( {1 - c} \right)}}$$     + $$\frac{1}{{\left( {1 - b} \right)\left( {1 - c} \right)\left( {1 - d} \right)}}$$     + $$\frac{1}{{\left( {1 - c} \right)\left( {1 - d} \right)\left( {1 - a} \right)}}$$     + $$\frac{1}{{\left( {1 - d} \right)\left( {1 - a} \right)\left( {1 - b} \right)}}$$     is?

If a + b + c + d = 4, then the value of $$\frac{1}{{\left( {1 - a} \right)\left( {1 - b} \right)\left( {1 - c} \right)}}$$     + $$\frac{1}{{\left( {1 - b} \right)\left( {1 - c} \right)\left( {1 - d} \right)}}$$     + $$\frac{1}{{\left( {1 - c} \right)\left( {1 - d} \right)\left( {1 - a} \right)}}$$     + $$\frac{1}{{\left( {1 - d} \right)\left( {1 - a} \right)\left( {1 - b} \right)}}$$     is?

In a box, there are 5 black pens, 3 white pens and 4 red pens. In how manyways can 2 black pens, 2 white pens and 2 red pens can be chosen?

Statements : Some pens are books. Some books are pencils.

Conclusions :
I. Some pens are pencils.
II. Some pencils are pens.
III. All pencils are pens.
IV. All books are pens.

Six arms negotiators -- M,O,P,R,S and T-- are to be seated at a round table to discuss disarmament. There are exactly six chairs around the table. Each negotiator sits facing the center of the table and is directly opposite a negotiators across the table.The seating arrangement is subject to the following restrictions : T cannot sit next to P;S cannot sit next to M;R must sit next to M. If T sits next to M and S sits next to R, which of the other negotiators must sit next to s ?

The value of the expression $$\frac{{{{\left( {a - b} \right)}^2}}}{{\left( {b - c} \right)\left( {c - a} \right)}} + $$   $$\frac{{{{\left( {b - c} \right)}^2}}}{{\left( {a - b} \right)\left( {c - a} \right)}} + $$    $$\frac{{{{\left( {c - a} \right)}^2}}}{{\left( {a - b} \right)\left( {b - c} \right)}}$$   = ?

The Hamiltonian of a particle is given by $$H = \frac{{{p^2}}}{{2m}} + V\left( {\left| {\overrightarrow {\bf{r}} } \right|} \right) + \phi \left( { + \left| {\overrightarrow {\bf{r}} } \right|} \right)\overrightarrow {\bf{L}} .\overrightarrow {\bf{S}} ,$$        where $$\overrightarrow {\bf{S}} $$ is the spin, $$V\left( {\left| {\overrightarrow {\bf{r}} } \right|} \right)$$  and $$\phi \left( {\left| {\overrightarrow {\bf{r}} } \right|} \right)$$  are potential functions and $$\overrightarrow {\bf{L}} \left( { = \overrightarrow {\bf{r}} \times \overrightarrow {\bf{p}} } \right)$$   is the angular momentum. The Hamiltonian does not commute with

$$\frac{{{{\left( {4.53 - 3.07} \right)}^2}}}{{\left( {3.07 - 2.15} \right)\left( {2.15 - 4.53} \right)}} + \, $$     $$\frac{{{{\left( {3.07 - 2.15} \right)}^2}}}{{\left( {2.15 - 4.53} \right)\left( {4.53 - 3.07} \right)}} + \,\, $$     $$\frac{{{{\left( {2.15 - 4.53} \right)}^2}}}{{\left( {4.53 - 3.07} \right)\left( {3.07 - 2.15} \right)}}$$     is simplified to :