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Special Drawing Right (SDR) এ কোন মুদ্ৰা ব্যবহৃত হয় না?
ক
ব্রিটিশ পাউন্ড
খ
চাইনিজ রেনমিনবি
গ
ফ্রেঞ্চ ফ্রাঁ
ঘ
জাপানিজ ইয়েন
সঠিক উত্তর:
ফ্রেঞ্চ ফ্রাঁ
Accept
Reject
Dismiss
One of the Primary functions of IMF is to provide short term capital assistance to member countries through SDR (Special Drawing Rights). What is NOT true about SDR?
ক
Currency code of SDR is XDR
খ
SDR is the Unit of Account of IMF
গ
Asian Development Bank (ADB) also uses SDR as its Currency
ঘ
None of the above
If a + b + c + d = 4, then find the value of $$\frac{1}{{\left( {1 - a} \right)\left( {1 - b} \right)\left( {1 - c} \right)}}$$ + $$\frac{1}{{\left( {1 - b} \right)\left( {1 - c} \right)\left( {1 - d} \right)}}$$ + $$\frac{1}{{\left( {1 - c} \right)\left( {1 - d} \right)\left( {1 - a} \right)}}$$ + $$\frac{1}{{\left( {1 - d} \right)\left( {1 - a} \right)\left( {1 - b} \right)}}$$ is?
ক
0
খ
5
গ
1
ঘ
4
If a + b + c + d = 4, then the value of $$\frac{1}{{\left( {1 - a} \right)\left( {1 - b} \right)\left( {1 - c} \right)}}$$ + $$\frac{1}{{\left( {1 - b} \right)\left( {1 - c} \right)\left( {1 - d} \right)}}$$ + $$\frac{1}{{\left( {1 - c} \right)\left( {1 - d} \right)\left( {1 - a} \right)}}$$ + $$\frac{1}{{\left( {1 - d} \right)\left( {1 - a} \right)\left( {1 - b} \right)}}$$ is?
ক
0
খ
1
গ
4
ঘ
1 + abcd
The value of the expression $$\frac{{{{\left( {a - b} \right)}^2}}}{{\left( {b - c} \right)\left( {c - a} \right)}} + $$ $$\frac{{{{\left( {b - c} \right)}^2}}}{{\left( {a - b} \right)\left( {c - a} \right)}} + $$ $$\frac{{{{\left( {c - a} \right)}^2}}}{{\left( {a - b} \right)\left( {b - c} \right)}}$$ = ?
ক
0
খ
3
গ
$$\frac{1}{3}$$
ঘ
2
The Hamiltonian of a particle is given by $$H = \frac{{{p^2}}}{{2m}} + V\left( {\left| {\overrightarrow {\bf{r}} } \right|} \right) + \phi \left( { + \left| {\overrightarrow {\bf{r}} } \right|} \right)\overrightarrow {\bf{L}} .\overrightarrow {\bf{S}} ,$$ where $$\overrightarrow {\bf{S}} $$ is the spin, $$V\left( {\left| {\overrightarrow {\bf{r}} } \right|} \right)$$ and $$\phi \left( {\left| {\overrightarrow {\bf{r}} } \right|} \right)$$ are potential functions and $$\overrightarrow {\bf{L}} \left( { = \overrightarrow {\bf{r}} \times \overrightarrow {\bf{p}} } \right)$$ is the angular momentum. The Hamiltonian does not commute with
ক
$$\overrightarrow {\bf{L}} + \overrightarrow {\bf{S}} $$
খ
$$\overrightarrow {{{\bf{S}}^2}} $$
গ
$${L_z}$$
ঘ
$$\overrightarrow {{{\bf{L}}^2}} $$
$$\frac{{{{\left( {4.53 - 3.07} \right)}^2}}}{{\left( {3.07 - 2.15} \right)\left( {2.15 - 4.53} \right)}} + \, $$ $$\frac{{{{\left( {3.07 - 2.15} \right)}^2}}}{{\left( {2.15 - 4.53} \right)\left( {4.53 - 3.07} \right)}} + \,\, $$ $$\frac{{{{\left( {2.15 - 4.53} \right)}^2}}}{{\left( {4.53 - 3.07} \right)\left( {3.07 - 2.15} \right)}}$$ is simplified to :
ক
0
খ
1
গ
2
ঘ
3
SDR (Special Drawing Rights) সুবিধা প্রবর্তনের জন্য কত সালে IMF এর গঠনতন্ত্র (Articles) সংশোধন করা হয়েছিল?
ক
১৯৬৯
খ
১৯৭১
গ
১৯৭৫
ঘ
১৯৭৮
A machine part is drawn two times with different scales. The ratio of 1st drawing’s R.F. to 2nd drawing R.F. with respect to the actual object is found to be 2. The length of the second drawing is 10 mm. Find the 1st drawing length.
ক
5 mm
খ
200 mm
গ
5 cm
ঘ
2 cm
The quark content of $$\sum {^ + } ,\,{K^ - },\,{\pi ^ - }$$ and p is indicated: $$\left| {\sum {^ + } } \right\rangle = \left| {uus} \right\rangle ;\,\left| {{K^ + }} \right\rangle = \left| {s\overline u } \right\rangle ;\,\left| \pi \right\rangle = \left| d \right\rangle ;\,\left| p \right\rangle = \left| {uud} \right\rangle $$
In the process, $${\pi ^ - } + p \to {K^ - } + \sum {^ + } ,$$ considering strong interactions only, which of the following statements is true?
ক
The process is allowed because ΔS = 0
খ
The process is allowed because $$\Delta {I_3} = 0$$
গ
The process is not allowed because ΔS ≠ 1 and $$\Delta {I_3} \ne 0$$
ঘ
The process is not allowed because the Baryon number is violated
Consider the differential equation $$\frac{{{{\text{d}}^2}{\text{y}}\left( {\text{t}} \right)}}{{{\text{d}}{{\text{t}}^2}}} + 2\frac{{{\text{dy}}\left( {\text{t}} \right)}}{{{\text{dt}}}} + {\text{y}}\left( {\text{t}} \right) = \delta \left( {\text{t}} \right)$$ with $${\left. {{\text{y}}\left( {\text{t}} \right)} \right|_{{\text{t}} = 0}} = - 2$$ and $${\left. {\frac{{{\text{dy}}}}{{{\text{dt}}}}} \right|_{{\text{t}} = 0}} = 0.$$
The numerical value of $${\left. {\frac{{{\text{dy}}}}{{{\text{dt}}}}} \right|_{{\text{t}} = 0}}$$ is
ক
-2
খ
-1
গ
0
ঘ
1