'The Times of India' which celebrated its 150th anniversary in 1988, was first published in 1838 as

'The Times of India' which celebrated its 150th anniversary in 1988, was first published in 1838 as Correct Answer Bombay Times

The Times of India issued its first edition on 3 November 1838 as The Bombay Times and Journal of Commerce.
History Modern Indian History
শেয়ার করুন বন্ধুর সাথে

বিসিএস, ব্যাংক, প্রাইমারি সহ সরকারি বেসরকারি চাকুরীর পরীক্ষার প্রস্তুতির জন্য ডাউনলোড করুন Bissoy অ্যাপ

Related MCQ's

Simplify the value of $$\frac{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} \times {\text{0}}{\text{.3}} - {\text{3}} \times 0.9 \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}}}}{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} - 0.9 \times {\text{0}}{\text{.2}} - {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}} - 0.3 \times 0.9}} = ?$$

$$\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}$$            is equal to = ?

$$\eqalign{ & {\text{The}}\,{\text{value}}\,{\text{of}} \cr & \frac{{0.1 \times 0.1 \times 0.1 + 0.02 \times 0.02 \times 0.02}}{{0.2 \times 0.2 \times 0.2 + 0.04 \times 0.04 \times 0.04}}\,\text{is}: \cr} $$

The value of $$\left( {\frac{{0.1 \times 0.1 \times 0.1 + 0.02 \times 0.02 \times 0.02}}{{0.2 \times 0.2 \times 0.2 + 0.04 \times 0.04 \times 0.04}}} \right)$$       is :

The value of $${\text{ }}\root 3 \of {\frac{{0.2 \times 0.2 \times 0.2 + 0.04 \times 0.04 \times 0.04}}{{0.4 \times 0.4 \times 0.4 + 0.08 \times 0.08 \times 0.08}}} $$        is ?

When my parents married their age was in a ratio 11 : 10 (father’s age : mother’s age). This year they celebrated 15th anniversary. If the total of their ages at their silver jubilee anniversary will be 113, find my father’s age now.

The value of $$\left( {\frac{{0.943 \times 0.943 - 0.943 \times 0.057 + 0.057 \times 0.057}}{{0.943 \times 0.943 \times 0.943 + 0.057 \times 0.057 \times 0.057}}} \right)$$         is :

Simplify : $$\frac{{0.41 \times 0.41 \times 0.41 + 0.69 \times 0.69 \times 0.69}}{{0.41 \times 0.41 - 0.41 \times 0.69 + 0.69 \times 0.69}} = ?$$

$$\frac{{768 \times 768 \times 768 + 232 \times 232 \times 232}}{{768 \times 768 - 768 \times 232 + 232 \times 232}} = ?$$

The value of :
$$\left( {\frac{{0.051 \times 0.051 \times 0.051 + 0.041 \times 0.041 \times 0.041}}{{0.051 \times 0.051 - 0.051 \times 0.041 + 0.041 \times 0.041}}} \right)$$

X